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x^2+14x=275
We move all terms to the left:
x^2+14x-(275)=0
a = 1; b = 14; c = -275;
Δ = b2-4ac
Δ = 142-4·1·(-275)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-36}{2*1}=\frac{-50}{2} =-25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+36}{2*1}=\frac{22}{2} =11 $
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